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-0018x^2+.06x+1.5=0
We add all the numbers together, and all the variables
-18x^2+.06x+1.5=0
a = -18; b = .06; c = +1.5;
Δ = b2-4ac
Δ = .062-4·(-18)·1.5
Δ = 108.0036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.06)-\sqrt{108.0036}}{2*-18}=\frac{-0.06-\sqrt{108.0036}}{-36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.06)+\sqrt{108.0036}}{2*-18}=\frac{-0.06+\sqrt{108.0036}}{-36} $
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